The Doppler effect

When the source S  is moving forwards at the speed Vs from the
observer, at the precise time T, which is the period of the wave,
this wave that was emitted from the position So reaches the observer.
The source at this time is not located at the distance So, but It 
was moved and now located at the distance L's.
For the observer, It seems that the wave was originated from the
position S taking T' as time to arrive at its position:
L's = Vw . T'
We have :
Ls = Vw . T
And :
L's = Ls + Vs. T
Thus:
Vw . T '= Vw . T +Vs. T
Then:
T' = T . (Vw + Vs)/Vw
Or :






Where n' is the apparent  frequency
for the Observer. 
n is the real frequency of the wave.


Remarks:

When the source is stationary (Vs =0)
then n' = n and T' = T,  that is the observer 
get waves at every real period.
 The more the speed Vs is big, the more the right edges
of the waves are squeezed and leaving behind distant 
position between the edges. In the front , we have what we
call the sound boom or the schok wave if the wave is a sound.




Next, the observer sit down on the frame O is at rest. The source 
S is moving at a speed Vs towards the Observer. The wave propagates
at the speed Vw in all directions and towards the observer of course.
When this observer receives the wave, at this precise time, the
source is located not in Ls but in L's. For the observer, the 
period od the wave is T's. And at this precise time, the wave has 
travelled Ls = Vs . T , where T is the real period . 
T's is  the apparent  period.

We can write:
L's = Ls - Vs . T
Because Ls = Vw . T
and L's = Vw . T's
Thus :
Vw . T's = Vw . T - Vs . T = (Vw - Vs) . T
Or 
1/T's = Vw /(Vw - Vs) (1/T)
Which  means that the apparent   frequency 














Remarks: 



 





Now, let's consider that the Observer is moving
at a speed Vo and the sourse is moving at a speed Vs, 
oppraching the observer, that is in the opposite direction. 
The wave is always moving at the velocity Vw.






This case is like the last one except that the observer 
is moving. Then insted of L's = Vw . T' , we have
L's = (Vw  + Vo) . T'
Thus :
(Vw  + Vo) . T'  = (Vw - Vs) . T
Hence:







In the relativistic case, the frequency ( 1/time) could be changed into:
1/gt
Where g = 1/(1- (V2/c2))1/2
Hence :
n' ( Relativistic) = (1/g) .  n ( Classic) 
For the latter case, we have:

n' = n .( (Vw+Vs)/(Vw-Vs))1/2 . (Vw+Vo)/Vw





In the case of the wave is light, Vw = c ( 3.10 8m/s)
Then :


n' = n .( (c+Vs)/(c-Vs))1/2 . (c+Vo)/c


In the cast of the Observer is at rest, V0 =0, then:
n' = n .( (c+Vs)/(c-Vs))1/2 .